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Determine whether the series converges or diverges by finding a telescoping sum: 2/((n^2)-1)
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\[\sum_{n=2}^{\infty} \frac{ 2 }{ n ^{2} -1} \] is the series
Thought I had this one figured out, but I get 1 where the answer is 3/2 ....
|dw:1351650608920:dw| Hmmmm I think this is how you want to solve this problem D: My guess at least..
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