Find the tangent of the line to the curve at the given point.

cos(x-y)+siny=sqrt(2)

(pi/2,pi/4)

tell me the steps? please.

Question

Find the tangent of the line to the curve at the given point.

cos(x-y)+siny=sqrt(2)

(pi/2,pi/4)

tell me the steps? please.

anonymous · Answer

more implicit differentiation and lots of chain rule :D

anonymous · Answer

$${\frac {\sin \left( x-y \right) }{\sin \left( x-y \right) +\cos  \left( y \right) }} $$

anonymous · Answer

sin(x-y)/(sin(x-y)+cos(y))

anonymous · Answer

your m will be 1/2 if you evaluate it at (pi/2,pi/4) 

then you use y=mx+b plug in y m and x and solve for b

anonymous · Answer