I need help with some homework.
Solve.

3x + 10 ≥ 4 (1 point)
x ≥ –2
x ≤ 2
x ≤ –2
x ≥ 2
4. The French Club is sponsoring a bake sale. If their goal is to raise at least $140.00, how many pastries must they sell at $3.50 each to meet that goal? Write and solve an inequality. (1 point)
3.50p ≥ 140; p ≥ 490
140p ≥ 3.50; p ≥ 40
3.50p ≥ 140; p ≥ 136.5
3.50p ≥ 140; p ≥ 40

Question

I need help with some homework.
   Solve. 

3x + 10 ≥ 4  (1 point)
x ≥ –2
x ≤ 2
x ≤ –2
x ≥ 2
4.   The French Club is sponsoring a bake sale. If their goal is to raise at least $140.00, how many pastries must they sell at $3.50 each to meet that goal? Write and solve an inequality.  (1 point)
3.50p ≥ 140; p ≥ 490
140p ≥ 3.50; p ≥ 40
3.50p ≥ 140; p ≥ 136.5
3.50p ≥ 140; p ≥ 40

anonymous · Answer

Solve the expression like a regular algebra problem. subtract 10 from each side first. then divide by 3. keep the sign the same. Let me know what you get.

anonymous · Answer

I'm not good with negative numbers

anonymous · Answer

think of it like this. We have 4 dollars and you Owe 10. So you give them the 4 and still owe 6. So you're 6 in the hole. or -6

anonymous · Answer

3x + 10 >= 4
3x >= -6
x >= -2