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Find the absolute maximum and absolute minimum values of the function f(x)=3x−11ln(3x) on the interval [1,6]. Enter DNE for any absolute extrema that does not exist.
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@hartnn can you give me a hand?
did u differentiate f(x) ? what u got ?
ya 3-11/x sorry god disconnected from the internet
yes, now equate that to 0 and solve for x
so x=11/3
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and x=0
yes, put that back in f(x) to get the critical value.
x=0 is incorrect.
11-11 log(11)
11-11 log(11) is one of the critical point .
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ok got it thank you
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