Question

A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2 + 608t.

After how many seconds does it reach its maximum height?

Answer 1

please help!!

Answer 2

its maximum is defined at its vertex

Answer 3

the vertex of \[ax^2+bx+c\]is defined when
\[x=-\frac b{2a}\]

Answer 4

38 s

19 s

28.5 s

9 s

those are the answer choices.. so woulnt it be 38 s

Answer 5

38 is how long it takes to hit the ground again

Answer 6

it would tak half that time to go up, then half of it to come back down again

Answer 7

so then it be 19s???

Answer 8

yep