Question

Quadratic Expressions

Answer 1

Your equation is:\[-\frac{1 }{ 2 }x^2- 2x-6\]Use the Quadratic formula:\[x = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2a }\] Fill in the values:
\[-(-2) \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}\]
\[2 \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}\]
-2^2 = 4
4(-1/2)(-6) = 12
1 * -1/2\[2\pm \frac{\sqrt{4 - 12} }{ -1 }\]\[2 \pm \frac{ \sqrt{-8} }{ -1 }\]\[2\pm \frac{ 2.83 }{ -1 }\]\[2\pm -2.38\]
2 + (-2.38) = -0.37
2 - (-2.38) = 2 + 2.38 = 4.38

So the two solutions for x are:
x = -0.37
and
x = 4.38

Answer 2

@BrennaM I hope this helps! (:

Answer 3

Thanks it did :)