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Solve the inequality. 6y – 8 ≤ 10
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y\< 3
how did you do that
add 8 to both sides so that the y is alone
you would have 6y<18
then divide by 6 on both sides
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18/6 is 3
can you put that in step form cause im confused
\[6y-8 \le 10\] First, add 8 to both sides. \[6y-8+8\le10+8\] \[6y \le18\] Divide 6 from both sides. \[6y \div6 \le 18\div6\] \[18\div6=3\] \[6y \div6=y\] \[y \le3\]
@I4NI Thank you
You're welcome.
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