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solve the equation x^2-2x-3=2 a, x=-3,-1 b,x=-1,-3 c,x=-3,-2 d, none of these
Are you familiar with the quadratic formula?
\[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\] But first, put the equation in the form ax^2 + bx + c = 0. Then make the necessary substitutions.
Start by subtracting 2 from each side of your original equation. Write out the new equation and I'll check your work and progress.
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