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Mathematics 10 Online
OpenStudy (anonymous):

(2+2cosx)/(sinx +sinxcosx) = 2cscx need some help verifying this identity

OpenStudy (anonymous):

Pretty straight forward pull out 2 from numerator as a COMMON FACTOR THEN PULL OUT SIN(X) FROM DENOMINATOR AS A COMMON FACTOR then cancel out ( 1+cos(x)) which is in NUM AND DEN. you have 2/sin(x) = 2 cosec (x)

OpenStudy (anonymous):

hope that helps you out : )

OpenStudy (anonymous):

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