Question

helpppppp plllzzzz



find the zeros of the function y=x^2-64

a,(8,0)and(8,0)
b,(8,0)and (-8,0)
c,(-8,0)and (-8,0)
d,(4,0)and(0,0)

Answer 1

x^2-64=x^2-8^2

does that help

Answer 2

difference of two squares

Answer 3

y = x^2 - 64
Set y = 0, then solve for x:

0 = x^2 - 64
64 = x^2

Take square root, both sides:

±8 = x

Thus:

(8,0) and (-8,0)

Answer 4

\[a^2-b^2=(a-b)(a+b)\]