Question

Solve the following in [0,2pi)
sin^3theta+2sin^2theta=sintheta+2

Answer 1

\[\sin ^{3}\theta+2\sin ^{2}\theta=\sin \theta+2\]

Answer 2

Pretend that \[\sin{\theta} = x\] solve the cubic and then resub in to solve for theta.

Answer 3

so would i factor it out?

Answer 4

sinx(sinx^2+2Sinx)=sinx+2

Answer 5

They are saying let x = sin theta

So, x^3 + 2x^2 = x + 2
Solve for x, then set that x value equal to sin theta

Answer 6

ok so would i subtract x from the right side and put it on the left having the equation =2