Question

how would you factor 27x^3-8y^3

Answer 1

x^3(27-8)=19x^3

Answer 2

rewrite

Answer 3

rewrite \[27x^{3} \] as \[(3x)^{3}\] and \[8y^{3}\] as \[(2y)^{3}\]
then apply the factoring method for \[a^{3}-b^{3}\]

Answer 4

@mayankdevnani you are doing it wrong.

Answer 5

thnx... @sirm3d