Question

solve and find the value of x .

3x^2+78=4x^2+7x

Answer 1

4x^2-3x^2+7x-78=0
x^2+7x-78=0
x^2+13x-6x-78
x(x+13)-6(x+13)=0
(x-6)(x+13)=0
x=6 & x=-13

Answer 2

\(3x^2+78=4x^2+7x\)
\(4x^2+7x-3x^2-78=0\)
\(x^2+7x-78=0\)
use quadratic formula to find x
\[x=\frac{-b\pm\sqrt{b^2-4ac} }{ 2a }\]
Here
a=1
b=7
c=-78