Question

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Answer 1

\[\Huge{\frac{1}{2x^2-x+5}=0}\]\[\Huge{\implies1=2x^2-x+5}\]\[\Huge{\implies x^2-x+5-1=0}\]\[\Huge{\implies x^2-x+4=0}\]use the quadratic formula now to solve for x :)

Answer 2

\[\Huge{\color{red}{{x}={-b \pm \sqrt{b^2-4ac}\over2a}}}\]

Answer 3

here
a=1
b=-1
c=4
so,\[\Huge{\color{green}{-(-1) \pm \sqrt{(-1)^2-4(1)(4)}\over2(1)}}\]

Answer 4

solv this to gt the value of 'x' :)