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OpenStudy (anonymous):
Show that \[x ^{2}+18\ln(x)+11>12x \] for x>1, I have no idea how to do the 18ln(x) messes things up for me...
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OpenStudy (anonymous):
good question. Not that I know how to do it....
OpenStudy (anonymous):
@frx try posting in the math section
OpenStudy (anonymous):
Ohh, sorry posted it wrong :p
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