Question

Last one:

Answer 1

\[\LARGE \frac{ 8 }{ 3 + \sqrt{2} }\]

Answer 2

multiply and divide by 3-\(\sqrt 2\)

Answer 3

then use \(\huge (a+b)(a-b)=a^2-b^2\)

Answer 4

\[\large A) \frac{ 8\sqrt{2} }{ 5 }\]
\[\large B) \frac{8\sqrt{2} }{ 3\sqrt{2} + 2}\]
\[\large C) \frac{ 24-8\sqrt{2} }{ 7 }\]
\[\large D) \frac{ 24-\sqrt{2} }{ 7 }\]

Answer 5

Wait, multiply & divide what to what?

Answer 6

\(\huge \LARGE \frac{ 8 }{ 3 + \sqrt{2} } \times \frac{3-\sqrt 2}{3-\sqrt 2}\)

Answer 7

hmm....

Answer 8

use this for denominator
\(\huge (a+b)(a-b)=a^2-b^2\)

Answer 9

a=3, b= \(\sqrt 2\)

Answer 10

okay. so 3+sqrrt2 = ????

Answer 11

what ?
\((3+\sqrt 2)(3-\sqrt 2)=3^2-(\sqrt 2)^2=?\)

Answer 12

Yeah, I was doing it piece by piece & then was going to multiply it all together & everything afterwards, haha. Sorry.

Answer 13

\(\large (3+\sqrt 2)(3-\sqrt 2)=3^2-(\sqrt 2)^2=?\)

Answer 14

umm, \[\Large 3\sqrt[2]{2}\] ????

Answer 15

I don't know how to find that answer...

Answer 16

3^2 = ?

Answer 17

27

Answer 18

wow!

Answer 19

What?

Answer 20

3^2 = 3*3 = ?

Answer 21

oooh, sorry. 9

Answer 22

i was thinking 3^3. My brain's not with it today.

Answer 23

\(\huge \sqrt 2^2 = 2^{(1/2)
*2}=?\)

Answer 24

1

Answer 25

?

Answer 26

\(\huge \sqrt 2^2 = 2^{(1/2)
*2}=2^1=?\)

Answer 27

2

Answer 28

so \(\large (3+\sqrt 2)(3-\sqrt 2)=3^2-(\sqrt 2)^2=?\)

Answer 29

2?

Answer 30

Oh, no 9-2, right?

Answer 31

yes.

Answer 32

Which equals 7. So the denominator is 7. Right?

Answer 33

yes

Answer 34

So, what do we do with the 8?

Answer 35

8(3-\(\sqrt 2\))=?

Answer 36

I don't know..

Answer 37

8*3= ?

Answer 38

24

Answer 39

so 24-8\(\sqrt 2\)

Answer 40

Ooooh, okay.

Answer 41

Thank you :D

Answer 42

welcome ^_^