Question

1. Solve the system by elimination.

Answer 1

You need to do 2 at a time.

Start with eq 2 & 3

2x -y + 5x = -9
2x - 10y - 5z = 0 subtract 2 from 1

2x -y + 5x = -9
-2x + 10y + 5z = 0 ( i changed the signs so we can add instead)

9y + 10z = -9

Now we have to to 1 & 3

x + 5y - 4z = -10 Multiply everything by -2
2x - 10y - 5z = 0

-2x - 10y + 8z = 20
2x - 10y - 5z = 0 (add them)

-20y + 3z = 20

Answer 2

So which is the answer?? (5, –1, 0)
(–5, 1, 0)
(–5, –1, 0)
(–5, –1, –2)

Answer 3

still working. Do you want to learn or just want the answer ?

Answer 4

answer would be great

Answer 5

good luck then

Answer 6

ok id love to learn