Question

Solve the equation in the intervals [0,2pi)
4sin^2x+2cos^2x=3

Answer 1

\[4\sin^2x+2\cos^2x=3\]

Answer 2

I here try this web site should work!
http://www.mathway.com
Let me know if this don't help you!
~Jess~

Answer 3

ok

Answer 4

it didnt give the exact values

Answer 5

oh okay... Sorry

Answer 6

Thanks anyway

Answer 7

ya i am sorry i won't that good as a help, let me look for other on okay! = )

Answer 8

here try this web site!
http://www.wolframalpha.com/