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sqrt(8 − 2x) = x − 4
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square both sides, what u get ?
8-2x=x-4
the right side also gets squared 8-2x = (x-4)^2 now expand right side.......
8-2x=x^2-16?
(x-a)^2 = x^2-2ax+a^2
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so, 8-2x = x^2-8x+16 now bring everything on one side
24-10x=x^2?
umm, nopes \(8-2x = x^2-8x+16 \\ x^2-8x+2x+16-8=0 \\ x^2-6x+8=0\) can u solve this quadratic ?
Would it be lame if i said i didn't know how xD
no, its okay. split the middle term \(x^2-4x-2x+8=0\)
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\(x(x-4)-2(x-4)=0\) can u solve ahead ?
yes
thank you
what u get?
x^2-4x-2x-8=0
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then combine like terms?
why u going reverse way? u will get your question back :P \(x(x-4)-2(x-4)=0 \\(x-4)(x-2)=0 \\ x=4 \:or\:x=2\) got this ?
Idk im dumb xD lol thank you!
welcome ^_^
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