Question

Solve exactly for the variable:

\[x-\frac{ 1 }{ 2 }x^3+\frac{ 1 }{ 3 }x^3+...=0.2\]

No idea how to do this. We are in taylor polynomial at the moment.

Answer 1

the 2nd term should be x^2

\[x-\frac{ 1 }{ 2 }x^2+\frac{ 1 }{ 3 }x^3+...=0.2\]

Answer 2

Any hints for starting this?