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Physics 16 Online
OpenStudy (anonymous):

vector 2

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

where it is??????????????????

OpenStudy (anonymous):

OpenStudy (anonymous):

\[A*B=ABcos \theta\] \[\cos \theta=\frac{ AB }{ A*B }\]

OpenStudy (anonymous):

|dw:1351803766879:dw| just find the modulus of AXB:)

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