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Write the quadratic function in vertex form. y = x2 + 16x + 74
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transpose the constant 74 then add 64 to both sides of the equation
how do i do that
\[y-74=x^2+16x\] \[y-74+64=x^2+16x+64\] \[y-10=(x+8)^2\]
so it would be y= (x+8)^2 +10
yes
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thank you so much man you been so helpful
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