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0.05x^2 -x+1 = -1+1 Im trying to figure out what would be my next step to finding the solutions through Completeing the square
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0.05x^2 -x+1 = -1+1 0.05x^2 -x+1 = 0 x^2 -20x+20 = 0 then using quadratic formula do you know??
how did you get that third step?
ok x = (-b +- sqrt(b^2-4ac)/2a x=(-(-20) +- sqrt((-20)^2 - (4 x1x 20))/2 x = (20 +- sqrt(320))/2 x = (20 +- 17.88)/2 So x = (20 + 17.88)/2 = 18.94 or x = (20 - 17.88)/2 = 1.06
divided all by 0.05 for third step @FlyinSolo_424
0.05x^2 -x+1 = -1+1 0.05x^2 -x+1 = 0 ((0.05x^2)/0.05) -(x/0.05)+(1/0.05) = (0/0.05) x^2 -20x+20 = 0
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Thank you So much For explaining I did it once I got that little thing nd I got the same anwser
welcome @FlyinSolo_424 , good job :)
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