Question

write a logarithmic form for 2^7=128

Answer 1

if \[a^b \]=N then\[\log_{a}N\]=b

Answer 2

plug that in

Answer 3

log2^128=7

Answer 4

I guess i dont really understand

Answer 5

here's something that may help you understand, what you are trying to find is what number do you have to raise 2 to, to get 128 in this case is the number 7

Answer 6

I get that part but how do I right it in logarithmic form ?

Answer 7

I thought i just told you

Answer 8

think of "log" as another word for power, so Log of base 2 raised to 128 = 7, or log2^128=7

Answer 9

ok that helps sorry takes me a little to understand math isnt my best subject

Answer 10

its alright not my best either i get some stuff easier than others

Answer 11

just keep working at it, and Youtube is usually helpful for me too

Answer 12

mtipton is right lol youtube taught me calc