Question

find the x and y intercepts of the line that is tangent to the curve y=x^3 at the point (-2, -8)

Answer 1

can you find the equation of the line?

Answer 2

-8= f ' (-2) *(-2) +b

Answer 3

if you can find the derivative you can find b...

Answer 4

so the derivative would be 3x^2?

Answer 5

yes

Answer 6

ok so if that is the derivative, then to find the slope i need to plug in terms...so would b=12?

Answer 7

f '(-2) = 3(-2)^2

Answer 8

12...

-8 = (12)(-2) +b

Answer 9

so b=16?

Answer 10

yep

Answer 11

y=12x+16

Answer 12

find the intercepts and you're done.

Answer 13

thank you so so much!!!

Answer 14

sure:)