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Mathematics 17 Online
OpenStudy (anonymous):

log (2)^12

OpenStudy (anonymous):

|dw:1351832924289:dw|

OpenStudy (anonymous):

???

OpenStudy (sirm3d):

\[2+\log_{2} 3\]

OpenStudy (anonymous):

Well, I don't know what your question is. Let n be log₂12. (n = log₂12) Convert it into exponent form: 2ⁿ = 12, if you want exponent form. If you want to calculate it, you can simplify log₂12 to ln12/ln2. Does this help?

OpenStudy (anonymous):

To get 2 + log₂3: log₂12 = log₂(3·4). = log₂4 + log₂3 = 2 + log₂3

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