the average of 5 consecutive integers starting from m as the first integer is n.What is the average of following integers?
m+1,m+3,m+5,m+7,m+9
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OpenStudy (anonymous):
given m+(m+1)+(m+2)+(m+3)+(m+4)=5n
or 5m+10=5n or m+2=n
now average of (m+1,m+3,m+5,m+7,m+9)=(m+1+m+3+m+5+m+7+m+9) /5
=(5m+25)/5 = m+5 = m+2 +3 =( m+2 )+3 =n+3 (as m+2=n)
OpenStudy (anonymous):
r u sure? @matricked
OpenStudy (anonymous):
if u know what is meant by average
then i have given complete answer ...
else i should tell u the average ..
so do u know what is meant by average in arithmetic..
OpenStudy (anonymous):
yes i do know.
OpenStudy (anonymous):
then i hope u can well understand any mistake/error in the solution..
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
the answer would be m+2?
OpenStudy (anonymous):
options are m+4
m+5
n+6
none
OpenStudy (anonymous):
@matricked
OpenStudy (raden):
it should be n+3
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