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Mathematics 20 Online
OpenStudy (anonymous):

If x is an real number then the maximum value of 6x - x^2 - 11

hartnn (hartnn):

using calculus?

OpenStudy (anonymous):

naah !!.. plz suggest a simple way..

hartnn (hartnn):

then u use the formula, the max or min value of quadratic function \(ax^2+bx+c\) is -b/2a

OpenStudy (anonymous):

hmmm.....how is dis formula derived

hartnn (hartnn):

using calculus :P

hartnn (hartnn):

or by finding the vertex of the parabola represented by ax^2+bx+c

OpenStudy (anonymous):

ohkk.,,....what according to you shud d ans,..?

hartnn (hartnn):

Compare your quadratic function with \(ax^2+bx+c\) find a,b,c Max. value is then, -b/2a what u get a and b as ?

OpenStudy (anonymous):

i got a as 1 n b as -6???..rite?

hartnn (hartnn):

|dw:1351847576252:dw| so what u get as a=? and b=?

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