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2cos(3x-pi/4)=-sqrt3 find all solutions.
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\[2\cos(3x-\frac{ \pi }{ 4 })=-\sqrt{3}\]
Start by dividing by 2.
You get cos(3x-pi/4)=-sqrt3/(2)
3x-pi/4=arccos(-sqrt3/2)
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would I not use cos(A+B)=cosAcosB-sinAsinB?
You could use that if you feel comfortable using that formula.
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