Question

(5 cot x + 1)(sin x + 7) = 0 approximate nearest degree within [0, 360)

Answer 1

5 cot x + 1 = 0
cot x = -0.2
tan x = -5

Answer 2

sin x + 7 = 0
gives no real values of x

Answer 3

tan x = -5 gives

2 values in 2nd and 4th quadrant

x = 180 - 78.69 = 101.31 or 360 - 78.69 = 281.31

to nearest degree solution is 101 , 281 degrees