Question

5.
What is a cubic polynomial function in standard form with zeros 1, –2, and 2?

Answer 1

subtract x from the given zeros and multiply them all together

Answer 2

1, –2, 2

1-x, –2-x, 2-x

f(x) = (1-x) (–2-x) (2-x)

Answer 3

Choices given.
f(x)= x3 + x2 – 3x + 4
f(x)= x3 + x2 – 4x – 2
f(x)= x3 + x2 + 4x + 4
f(x)= x3 – x2 – 4x + 4

Answer 4

then you would need to pass a negative thru my results to get one of those

Answer 5

my solution: http://www.wolframalpha.com/input/?i=+%281-x%29+%28%E2%80%932-x%29+%282-x%29

one of the options: http://www.wolframalpha.com/input/?i=+%28x-1%29+%28x%2B2%29+%28x-2%29

Answer 6

subtract each root from its own x, then multiply the binomials formed.