Question

How many real zeroes does y = ( x + 8 )^3 + 9 have?

Answer 1

one only. the two other zeroes not real.

Answer 2

1
2
3
0

those are the choices

Answer 3

1.

Answer 4

it looks just like \(y=x^3\) only shifted to the left 8 units and up 9 units
\(y=x^3\) only has one zero
we can find it if you like

Answer 5

thank you :)

Answer 6

\[(x+8)^3+9=0\]
\[(x+8)^3=-9\]
\[x+8=\sqrt[3]{-9}\]
\[x=-8+\sqrt[3]{-9}\]

Answer 7

thanks:)