Question

A bus moves away from rest at a bus stop with an acceleration of 1ms^-2. As the bus stars to move a man who is 4m behind the stop runs with a constant speed after the bus. If he just manages to catch the bus find his speed?

Answer 1

hey.., what's the value of speed of a bus??

Answer 2

That is all the question

Answer 3

ok...,

s = vo.t + 0.5 a t^2
4 = 0 + 0.5 (1). t^2
t^2 = 4/0.5
t^2 = 8
t = sqrt(8)

vt = vo + at
vt = 0 + (1 x sqrt(8))

Answer 4

Yeah that fits the answer which is root8, thanks a lot

Answer 5

welcome