PLEASE HELP??

What are the solutions of the system?
y = x^2-3x+2
y=4x-4

A. (1, 0) and (–6, –28)

B. (1, 20) and (6, 0)

C. (1, 0) and (6, 20)

D. no solution

A, B, C, or D? (:

Question

PLEASE HELP??

What are the solutions of the system?
y = x^2-3x+2
y=4x-4

A. (1, 0) and (–6, –28)	

B. (1, 20) and (6, 0)	

C. (1, 0) and (6, 20)	

D. no solution

A, B, C, or D? (:

anonymous · Answer

THe solution to a system will represent where the functions meet each other.  At this point the x and y values of each function will be the same.  This allows you to set up the following equation:
$$y_1=y_2$$
since you know what y1 and y2 are equal to, sub those in now:
$$x^2-3x+2=4x-4$$
now you have one unknown (x) and one equation, this mean that you are able to find the value of x which satifies the equation, moving the equation around:
$$x^2-7x+6=0$$
A quadratic form, from here you should be able to solve for x (giving to solutions), and plugging into either of the origional equations for y to find the point set.