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Mathematics 6 Online
OpenStudy (anonymous):

lim of x^(1/x) as x-> 0+

hartnn (hartnn):

L=lim x->0+ x^(1/x) ln L = ln (lim x->0+ x^(1/x)) ln L = lim x->0+ ln [x^(1/x)] can u solve further ?

OpenStudy (anonymous):

\[e^\lim_{x \rightarrow 0}lnx/x\]

OpenStudy (anonymous):

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