Solve the following equations for x between 0 and 360 degrees (a) sinx + 4cos^2x = 1 (b) 2sec^2x = 3 - tan^2x For part (a) I have gotten this far: (4sinx + 3) (sinx - 1) = 0 How to I solve for x from there? Same applies to part (b): (tanx - 1) (tanx + 3) = 0. How to solve for x? Please show all working thanks.

Question

Solve the following equations for x between 0 and 360 degrees  (a) sinx + 4cos^2x = 1  (b) 2sec^2x = 3 - tan^2x  For part (a) I have gotten this far: (4sinx + 3) (sinx - 1) = 0 How to I solve for x from there?  Same applies to part (b): (tanx - 1) (tanx + 3) = 0. How to solve for x?  Please show all working thanks.

anonymous · Answer

post in Mathematics not Chemistry,you will be helped swiftly