Please help... A plane heads west (180.0 degrees) at a speed of 400.0 mph. The wind's velocity is southeast (315.0 degrees) at 30. mph.

What is Ax, the magnitude of the original vector of the plane?

Question

Please help... A plane heads west (180.0 degrees) at a speed of 400.0 mph. The wind's velocity is southeast (315.0 degrees) at 30. mph. 

What is Ax, the magnitude of the original vector of the plane?

anonymous · Answer

Let resultant vector R, Wind vector W, A is Plane vector:
A = R - W
Ax = Rx - Wx
     = 400 * cos 180 - 30 cos 45
     = -400 - 30√2/2  = - 421.21