y = cos x; [0, 4π]; a = 1/2
what are you supposed to do here?
the question says... find all the values of x such that for the real number a
and you have to do it in respect to [0,4pi]
now your question says find x at which y=1/2 that means cosx=1/2 x=60, and cos is positive in fourth quadrant 240 degrees , pi/3 and 4pi/3
now pi/3 and 4pi/3 is in the range of (0,2pi) now next two will be 5pi/3 and 3pi
i can't get it right i typed those in and it keeps saying wrong
solution is \[\frac{ \pi }{ 3 },\frac{ 4 \pi }{ 3 },\frac{ 5 \pi }{ 3 },3 \pi\]
it says… y=a and then what does x equal?
its not working
if y=a then y=1/2 because a=1/2 therefore cos x= 1/2 and x= pi/3
cos 60 = 1/2
i know thats how i did it but its wrong
then i guess solution is wrong, do you have options?
no its open ended
then dude x= pi/3 is the answer and all those that i mentioned above in the interval (0, 4pi)
tried it
then there is problem with solution i mean there is some error
i couldn't get any of them for the problems that were like this
try in radians, degrees and grads may be one of them will fit in
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