Question

find the critical points of f(x)=sinx-cos^2x in (0,2pi)

Answer 1

What did you get for the 1st Derivative?

Answer 2

cos(x)+sin(2 x)

Answer 3

Use chain rule.

Answer 4

cos(x) (1+2 sin(x))

Answer 5

Nope.

Answer 6

Actually, you have it. Now, where is it zero?

Answer 7

yes it is dido525 http://www.wolframalpha.com/input/?i=sin%28x%29-cos%5E2%28x%29+derivative

Answer 8

Yeah. I remember. Trig identity :P .

Answer 9

....

Answer 10

smh

Answer 11

nevermind i have the answer

Answer 12

You fooled me. You had it right in the 1st place. Excellent work.