Can anyone show me how to do this problem and explain how do do it? [2x 3 3z]=[5 3y 9]
im sorry buti dont understand the problem even though im really good at math sorry i cant help you unless you give me more detail
Solve The Equation haha Sorry forgot to put tht. :)
do you know what z and y are and is x a symbol also or is it a multiplication sign
like what they stand for
You have three unknowns, you need three equations at least to solve it.
thts what i was thinking preetha
the book does not say it says: Solve each equation: 1). [2x 3 3z]=[5 3y 9] thats what it says to do
= stands for multiply rite?
no equal means that they are gonna equal the same amount when done
oh. idk how we could do tht then
so what u basically have to do is think of a number for x and z and then solve the equation and think of a number for y so that when the equation y is solved in it will equal the same answer as u got when u solved the equation with x and z in it
i found an example in the book.. want me to post it?
sure
\[\left(\begin{matrix}y \\ 3x\end{matrix}\right)=\left[\begin{matrix}6 - 2x \\ 31 + 4y\end{matrix}\right]\] y=6-2x 3x=31+4y This system could be solved by using substitution: 3x=31+4y Second Equation 3x=31+4(6-2x) Substitute 6-2y for y 11x=55 Add 8x to each side x=5 Divide each side by 11 To find the value for y, substitute 5 for x in either equation: y=6-2x First equation y=6-2(5) Substitute 5 for x y=-4 Simplify The Solution is (5,-4)
() is for matrices
yea i dont understand this sorry
ok
Ok, that makes sense. This is matrix algebra. Format your question in a matrix form. And substitute the first line in the second, just like the example.
ok thank you
soo i would do it that to this one?? [2x 3 3z]=[5 3y 9] but if soo i dont see how, can you show me preetha?
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