Question

Another hard one >:(
posting prob

Answer 1

\[\left[\begin{matrix}3x-5 & x+y \\ 12 & 9z\end{matrix}\right]=\left[\begin{matrix}10 & 8 \\ 12 & 3x+y\end{matrix}\right]\]
Solve Equation

Answer 2

do the same way like i showed you in previous problem

Answer 3

Gahhh soo confusing

Answer 4

x=5 y=3 z=2
3(5)-5=15 5+3=8
12=12 9(2)=3(5)+3

Answer 5

3x-5=10
x+y=8
12=12
9z=3x+y
from 1º equation: x=5
from 2º: y=3
from 4º: z=(15+3)/9=2