Question

Simplify completely

Answer 1

\[\frac{ 2x^2+20x+32 }{ x^2-2x-80 }\]

Answer 2

Factor the numerator: (2x + 4)(x + 8)
Factor denominator: (x + 8)(x - 10)

Cancel the common factors in numerator and denominator. (x+8)

You are left with : \[\frac{ (2x+4) }{ (x+8) }\]

Answer 3

I lied. The denominator is (x-10)