find the angle between the given vectors to the nearest tenth of a degree. u=<8,4> , v=<9,9> options are 81.6 degrees 25.8 degrees 35.8 degrees 71.6 degrees Thankyou for the help :)
Dot product is handy for that.
it is multiple choice
It sure is.
Like CliffSedge said: \[\frac{ a * b }{ \left| a \right|\left| b \right| } = Cos \theta \] Where * = dot (dot product)
In your case a<8,4> b<9,9> dot product is : 72 + 36 = 108 magnitude of a : \[\sqrt{8^2 + 4^2}\] magnitude of b: \[\sqrt{9^2 + 9^2}\]
I'm not getting one of those answer choices.. How about you, @infoshark ?
Flying out to lunch as we speak, will take a peak when I return. Sorry Cliff. Girlfriend has me well trained.
Understood.
@cookiemonsta , are you sure those are the correct answers for this? Did you possibly not copy down the question properly?
I'm getting somewhere around 18 degrees, give or take, how about you @CliffSedge ?
I don't remember, but yeah, it was something like 18.5
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