Question

the sum of three numbers is 19.
the sum of twice the first number, 3 times the second number, and four times the third number is 61.
the difference between 4 times the first number and second number is 9.
Find all three numbers

Answer 1

x+y+z=19
2x+3y+4z=61
4x-y=9

Answer 2

i got x=-12 y=-57 z=88

Answer 3

i got x=4 , y=7, z=8

Answer 4

how

Answer 5

x+y+z=19 ------------multiply by -4
2x+3y+4z=61

Answer 6

ok i did that

Answer 7

-2x-y=-15

Answer 8

-2x-y=-15
4x-y=9
---------------subtract

Answer 9

or multiply by -1 then add

Answer 10

@Mandy86 got it?

Answer 11

yes thank you can u also check my work

Answer 12

on my other question

Answer 13

i did, good job