Question

6^(x+1)=12^(x)
this equation needs to use the logarithm.

Answer 1

Take log for both sides, that is
\[\log6^{x+1}=\log12^{x}\]Then, use log property \[logx^a = alogx\]\[(x+1)\log6=x\log12\]Can you solve it now?

Answer 2

yes, I can
thank you:)

Answer 3

Welcome :)