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Mathematics 6 Online
OpenStudy (anonymous):

find the solution of : (show all steps)

OpenStudy (anonymous):

|dw:1352017799092:dw|

OpenStudy (calculusfunctions):

@tanjung what is the inverse operation of a square root?

OpenStudy (calculusfunctions):

In other words, how do you undo a square root?

OpenStudy (calculusfunctions):

@tanjung if you don't know the answer to a question I ask, please do not be embarrassed to admit it. I want to teach you, not just give you the answers.

OpenStudy (anonymous):

ok, sir... does both sides have to square ?

OpenStudy (calculusfunctions):

Yes, excellent @tanjung ! Thus our first step will be to square both sides of the equation. @tanjung please note that we also have to find the domain (any restriction on the variable). We may do that either now or later, however I recommend we do it at the beginning. Do you know how to find the domain?

OpenStudy (anonymous):

but, let in left side be 1/2 and right side -1 1/4 not >= 1, sir ??

OpenStudy (anonymous):

i think, we cant squaring both sides sir

OpenStudy (calculusfunctions):

@tanjung your response is not very clear. Are you saying that the restriction is that x cannot be greatrer than or equal to one??

OpenStudy (calculusfunctions):

@tanjung square both sides is exactly what we need to do to solve for x. But first I'm asking you to find the domain.

OpenStudy (anonymous):

for domain x^2-2x >= 0 ?

OpenStudy (calculusfunctions):

Yes but we can't just leave it like that. So what do we do next?

OpenStudy (calculusfunctions):

Hint: Factor the left side of x² - 2x ≥ 0.

OpenStudy (anonymous):

ok, x^2-2x >= 0 x(x-2) >= 0 for zeros, x=0 or x=2

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