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An acute angle θ is in a right triangle with cos θ =(5)/(6) . What is the value of sec θ? and An acute angle θ is in a right triangle with sin θ = (5)/(6) . What is the value of cot θ?
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\[\sec\theta=\frac{ 1 }{ \cos\theta }\] can u find the value of \(sec\theta\) @TGNG?
When doing the first problem you must remember that cos and sec are opposite. Cos = adj/hyp and sec=hyp/adj. Therefore, if cos is 5/6, then sec is 6/5. It works the same way with the second part.
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