Question

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Answer 1

\[\sqrt{x+2}+4=x\]
\[\sqrt{x+2}=x-4\]
\[x+2=(x-4)^{2}\]
\[x+2=x ^{2}-8x+16\]
\[x ^{2}-9x+14=0\]
(x-7)(x-2)=0
So x=7 or x=2

Answer 2

just x=7 only,
x=2 not satisfy