Question

Why isn't the following function discontinuous at x=-3 (click to see)

Answer 1

\[\frac{ x^2+6x+9 }{ |x|+3 }\]

Answer 2

Factoring the numerator yields (x+3)(x+3)

Answer 3

oh nvm i understand

Answer 4

wouldn't the function be 1 at x=-3?

Answer 5

The function will be zero at -3.

Answer 6

But for the function to be discontinuous the function value must be undefined. Now I get it...