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OpenStudy (anonymous):
Please help . A jar contains 6 yellow and 8 blue gumballs. Two gumballs will be drawn at random without being replaced. If the first gumball drawn is blue, what is the probability that the second gumball will also be blue? Leave answer as fraction. I have 7/13 as the answer
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OpenStudy (kropot72):
Your answer is correct. When the first gumball drawn is blue there are 7 blue gumballs remaining. The total number of gumballs remaining is 13. Therefore the probability of drawing a second blue gumball on the second draw is 7/13.
OpenStudy (anonymous):
Thank you
OpenStudy (kropot72):
You're welcome :)
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